jackbenny/simplog
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Renamed users table so it doesn't conflict with another site, in case you use the same database.

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This commit is contained in:
Elyrith 2013-08-11 22:44:10 -04:00
parent 4a1fe7bad6
commit be86ecdaa1
2 changed files with 4 additions and 4 deletions
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2
includes/login.inc
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@ -10,7 +10,7 @@ if ( $_COOKIE['session'] ) { // If yes, continue loading page as normal
# Attempt login
require "dbconnect.php";
$sql = "SELECT id,username FROM users WHERE username='$_POST[username]' and password=PASSWORD('$_POST[password]')";
$sql = "SELECT id,username FROM blog_users WHERE username='$_POST[username]' and password=PASSWORD('$_POST[password]')";
$result = mysql_query($sql) or die (mysql_error());
# echo "Results: " . mysql_num_rows($result); // Debugging line

6
install.php
View File

@ -26,8 +26,8 @@ if (mysql_error()) {
echo "Table 'Blog' created successfully.<br />";
}
# Try to create 'users' table
$sql = "CREATE TABLE `users` (`id` int(11) NOT NULL AUTO_INCREMENT,`username` varchar(20) NOT NULL,`name` varchar(40) NOT NULL,`password` varchar(64) NOT NULL,`salt` int(64) NOT NULL,`session` int(64), PRIMARY KEY (`id`)) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;";
# Try to create 'blog_users' table
$sql = "CREATE TABLE `blog_users` (`id` int(11) NOT NULL AUTO_INCREMENT,`username` varchar(20) NOT NULL,`name` varchar(40) NOT NULL,`password` varchar(64) NOT NULL,`salt` int(64) NOT NULL,`session` int(64), PRIMARY KEY (`id`)) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;";
$result = mysql_query($sql);
if (mysql_error()) {
echo mysql_error() . ".<br />";
@ -36,7 +36,7 @@ if (mysql_error()) {
}
# Try to create 'admin' user
$sql = "INSERT INTO `users` (`id`, `username`, `name`, `password`, `session`) VALUES (NULL, 'admin', 'Admin', PASSWORD('admin'), RAND(10000), NULL);";
$sql = "INSERT INTO `blog_users` (`id`, `username`, `name`, `password`, `session`) VALUES (NULL, 'admin', 'Admin', PASSWORD('admin'), RAND(10000), NULL);";
$result = mysql_query($sql);
if (mysql_error()) {
echo "User 'admin' already exists.<br />";